Đại số tuyến tính Ví dụ

$[\begin{array}{c} - 6 & 7 \\ 2 & 6 \\ - 4 & 1 \end{array}]$

Bước 1

Multiply each element of $R_{1}$ by $- \frac{1}{6}$ to make the entry at $1, 1$ a $1$ .

Nhấp để xem thêm các bước...

Bước 1.1

Multiply each element of $R_{1}$ by $- \frac{1}{6}$ to make the entry at $1, 1$ a $1$ .

$[\begin{array}{c} - \frac{1}{6} \cdot - 6 & - \frac{1}{6} \cdot 7 \\ 2 & 6 \\ - 4 & 1 \end{array}]$

Bước 1.2

Rút gọn $R_{1}$ .

$[\begin{array}{c} 1 & - \frac{7}{6} \\ 2 & 6 \\ - 4 & 1 \end{array}]$

Bước 2

Perform the row operation $R_{2} = R_{2} - 2 R_{1}$ to make the entry at $2, 1$ a $0$ .

Nhấp để xem thêm các bước...

Bước 2.1

Perform the row operation $R_{2} = R_{2} - 2 R_{1}$ to make the entry at $2, 1$ a $0$ .

$[\begin{array}{c} 1 & - \frac{7}{6} \\ 2 - 2 \cdot 1 & 6 - 2 (- \frac{7}{6}) \\ - 4 & 1 \end{array}]$

Bước 2.2

Rút gọn $R_{2}$ .

$[\begin{array}{c} 1 & - \frac{7}{6} \\ 0 & \frac{25}{3} \\ - 4 & 1 \end{array}]$

Bước 3

Perform the row operation $R_{3} = R_{3} + 4 R_{1}$ to make the entry at $3, 1$ a $0$ .

Nhấp để xem thêm các bước...

Bước 3.1

Perform the row operation $R_{3} = R_{3} + 4 R_{1}$ to make the entry at $3, 1$ a $0$ .

$[\begin{array}{c} 1 & - \frac{7}{6} \\ 0 & \frac{25}{3} \\ - 4 + 4 \cdot 1 & 1 + 4 (- \frac{7}{6}) \end{array}]$

Bước 3.2

Rút gọn $R_{3}$ .

$[\begin{array}{c} 1 & - \frac{7}{6} \\ 0 & \frac{25}{3} \\ 0 & - \frac{11}{3} \end{array}]$

Bước 4

Multiply each element of $R_{2}$ by $\frac{3}{25}$ to make the entry at $2, 2$ a $1$ .

Nhấp để xem thêm các bước...

Bước 4.1

Multiply each element of $R_{2}$ by $\frac{3}{25}$ to make the entry at $2, 2$ a $1$ .

$[\begin{array}{c} 1 & - \frac{7}{6} \\ \frac{3}{25} \cdot 0 & \frac{3}{25} \cdot \frac{25}{3} \\ 0 & - \frac{11}{3} \end{array}]$

Bước 4.2

Rút gọn $R_{2}$ .

$[\begin{array}{c} 1 & - \frac{7}{6} \\ 0 & 1 \\ 0 & - \frac{11}{3} \end{array}]$

Bước 5

Perform the row operation $R_{3} = R_{3} + \frac{11}{3} R_{2}$ to make the entry at $3, 2$ a $0$ .

Nhấp để xem thêm các bước...

Bước 5.1

Perform the row operation $R_{3} = R_{3} + \frac{11}{3} R_{2}$ to make the entry at $3, 2$ a $0$ .

$[\begin{array}{c} 1 & - \frac{7}{6} \\ 0 & 1 \\ 0 + \frac{11}{3} \cdot 0 & - \frac{11}{3} + \frac{11}{3} \cdot 1 \end{array}]$

Bước 5.2

Rút gọn $R_{3}$ .

$[\begin{array}{c} 1 & - \frac{7}{6} \\ 0 & 1 \\ 0 & 0 \end{array}]$

Bước 6

Perform the row operation $R_{1} = R_{1} + \frac{7}{6} R_{2}$ to make the entry at $1, 2$ a $0$ .

Nhấp để xem thêm các bước...

Bước 6.1

Perform the row operation $R_{1} = R_{1} + \frac{7}{6} R_{2}$ to make the entry at $1, 2$ a $0$ .

$[\begin{array}{c} 1 + \frac{7}{6} \cdot 0 & - \frac{7}{6} + \frac{7}{6} \cdot 1 \\ 0 & 1 \\ 0 & 0 \end{array}]$

Bước 6.2

Rút gọn $R_{1}$ .

$[\begin{array}{c} 1 & 0 \\ 0 & 1 \\ 0 & 0 \end{array}]$